Answer
$0$
Work Step by Step
$\lim _{x\rightarrow \infty }\dfrac {\ln x}{x^{2}}=\dfrac {\dfrac {d}{dx}\left( \ln x\right) }{\dfrac {d}{dx}\left( x^{2}\right) }=\dfrac {\dfrac {1}{x}}{2x}=\dfrac {1}{2x^{2}}=0$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.