Answer
$\dfrac {3}{5}=0.6$
Work Step by Step
$\lim _{x\rightarrow 0}\dfrac {\sin 3x}{\sin 5x}=\dfrac {\dfrac {d}{dx}\left( \sin 3x\right) }{\dfrac {d}{dx}\left( \sin 5x\right) }=\dfrac {3\cos 3x}{5\cos 5x}=\dfrac {3\times \cos 0}{5\times \cos 0}=\dfrac {3\times 1}{5\times 1}=\dfrac {3}{5}=0.6$
