Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.7 Exercises - Page 564: 42

Answer

$\cos 1\approx 0.54$

Work Step by Step

$\lim _{x\rightarrow 1^+}\dfrac {\int ^{x}_{1}\cos \theta d\theta }{x-1}=\dfrac {\dfrac {d}{dx}\left( \int ^{x}_{1}\cos \theta d\theta \right) }{\dfrac {d}{dx}\left( x-1\right) }=\dfrac {\cos x}{1}=\cos 1\approx 0.54$
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