Answer
$\infty$
Work Step by Step
$\lim _{x\rightarrow \infty }\dfrac {x^{3}}{x+2}=\dfrac {\dfrac {d}{dx}\left( x^{3}\right) }{\dfrac {d}{dx}\left( x+2\right) }=\dfrac {3x^{2}}{1}=3x^{2}=\infty $
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