Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.7 Exercises - Page 564: 27

Answer

$0$

Work Step by Step

$\lim _{x\rightarrow \infty }\dfrac {x^{3}}{e^{\dfrac {x}{2}}}=\dfrac {\dfrac {d}{dx}\left( x^{3}\right) }{\dfrac {d}{dx}\left( e^{\dfrac {x}{2}}\right) }=\dfrac {3x^{2}}{\dfrac {1}{2}e^{\dfrac {x}{2}}}=\dfrac {\dfrac {d}{dx}\left( 3x^{2}\right) }{\dfrac {d}{dx}\left( \dfrac {1}{2}e^{\dfrac {x}{2}}\right) }=\dfrac {6x}{\dfrac {1}{4}e^{\dfrac {x}{2}}}=\dfrac {\dfrac {d}{dx}\left( 6x\right) }{\dfrac {d}{dx}\left( \dfrac {1}{4}e^{\dfrac {x}{2}}\right) }=\dfrac {6}{\dfrac {1}{8}e^{\dfrac {x}{2}}}=\dfrac {6}{\infty }=0$
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