Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Test - Page 578: 9



Work Step by Step

Simplify. $\sqrt[5] {\dfrac{-32}{x^{10}}}$ Therefore, $\sqrt[5] {\dfrac{-32}{x^{10}}}=\sqrt[5] {(\dfrac{-2}{x^2})^5}$ Thus, the given radical term can be written as:$\dfrac{-2}{x^2}$
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