Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Test - Page 578: 17


$52-14\sqrt 3$

Work Step by Step

Simplify. $(7 -\sqrt 3)^2 $ Since, $(a-b)^2=a^2+b^2-2ab$ Therefore, $(7 -\sqrt 3)^2 =49+3-14\sqrt 3$ or, $=52-14\sqrt 3$ Thus, the given radical term can be written as: $52-14\sqrt 3$
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