Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Test - Page 578: 14

Answer

$2x\sqrt[3] { x }$.

Work Step by Step

The given expression is $\frac{\sqrt[3] {16x^8}}{\sqrt[3] {2x^4}}$ Use quotient rule. $\sqrt[3] {\frac{ {16x^8}}{2x^4}}$ Factor the given expression: $=\sqrt[3] {\frac{{2^3\cdot 2\cdot x^3\cdot x^3\cdot x^2}}{{2x^3\cdot x}}}$ Simplify. $=\sqrt[3] {2^3\cdot x^3\cdot x }$ $=2\cdot x\sqrt[3] { x }$ $=2x\sqrt[3] { x }$.
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