Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Test - Page 578: 28

Answer

$-6+0i$.

Work Step by Step

The given expression is $=\sqrt{-9}\cdot \sqrt{-4}$ $=\sqrt{3^2\cdot (-1)}\cdot \sqrt{2^2\cdot (-1)}$ Use product rule. $=\sqrt{3^2}\cdot \sqrt{(-1)}\cdot \sqrt{2^2}\cdot \sqrt{(-1)}$ Use $\sqrt{(-1)}=i$ $=3i\cdot 2i$ Multiply. $=6i^2$ Use $i^2=-1$. $=-6$. Rewrite as $a+ib$. $=-6+0i$.
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