Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Test - Page 578: 1


a) 6, b) $x \leq 4$

Work Step by Step

Given: $f9x)=\sqrt{8-2x}$ a) Need to find $f(-14)$ $f(-14)=\sqrt{8-2(-14)}=\sqrt{36}=6$ b) Domain can be determined as follows: $8-2x\geq 0$ or, $-2x\geq -8$ or, $2x \leq 8$ Thus, $x \leq 4$
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