## Intermediate Algebra for College Students (7th Edition)

a) 6, b) $x \leq 4$
Given: $f9x)=\sqrt{8-2x}$ a) Need to find $f(-14)$ $f(-14)=\sqrt{8-2(-14)}=\sqrt{36}=6$ b) Domain can be determined as follows: $8-2x\geq 0$ or, $-2x\geq -8$ or, $2x \leq 8$ Thus, $x \leq 4$