## Intermediate Algebra for College Students (7th Edition)

$\dfrac{1}{81}$
Simplify. $27^{\frac{-4}{3}}$ $27^{\frac{-4}{3}}=(3^3)^{\frac{-4}{3}}$ or, $=(3)^{(3)(\frac{-4}{3})}$ Thus, $=3^{-4}$ It can be written as $\dfrac{1}{81}$