Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Test - Page 578: 2



Work Step by Step

Simplify. $27^{\frac{-4}{3}}$ $27^{\frac{-4}{3}}=(3^3)^{\frac{-4}{3}}$ or, $=(3)^{(3)(\frac{-4}{3})}$ Thus, $=3^{-4}$ It can be written as $\dfrac{1}{81}$
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