#### Answer

$2x\sqrt[4]{2y^3}$

#### Work Step by Step

Simplify. $\sqrt[4] {8x^3y} \sqrt[4] {4xy^2}$
Therefore, $\sqrt[4] {8x^3y} \sqrt[4] {4xy^2}=\sqrt[4]{(8x^3y)(4xy^2)}=\sqrt[4] {32x^4y^3}$
or, $=\sqrt[4]{16x^4} \sqrt[4]{2y^3}$
Thus, the given radical term can be written as:$2x\sqrt[4]{2y^3}$