Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Test - Page 578: 11



Work Step by Step

Simplify. $\sqrt[4] {8x^3y} \sqrt[4] {4xy^2}$ Therefore, $\sqrt[4] {8x^3y} \sqrt[4] {4xy^2}=\sqrt[4]{(8x^3y)(4xy^2)}=\sqrt[4] {32x^4y^3}$ or, $=\sqrt[4]{16x^4} \sqrt[4]{2y^3}$ Thus, the given radical term can be written as:$2x\sqrt[4]{2y^3}$
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