Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Test - Page 578: 16

Answer

$26+ 6 \sqrt 3$

Work Step by Step

Simplify. $(5\sqrt 6-2\sqrt 2) (\sqrt 6+\sqrt 2) $ Therefore, $(5\sqrt 6-2\sqrt 2) (\sqrt 6+\sqrt 2)=5 \cdot 6+5 \sqrt{6 .2}-2\sqrt {2.6}-4$ or, $=30+3 \sqrt{12}-4$ or, $=26+3 \sqrt{12}$ or, $=26+3 \sqrt{ 3 \cdot 4}$ Thus, the given radical term can be written as: $26+ 6 \sqrt 3$
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