Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Test - Page 578: 30



Work Step by Step

Solve $i^{35}$ Since, $i^2=-1$ and $i^2 \cdot i^2=(-1)(-1)=1$ and $i^3=i^2 \cdot i=-i$ Thus, $i^{35}=(i^2)^{7} \cdot i=(-1)^{7} \cdot i$ Hence, $i^{35}=-i$
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