#### Answer

$2xy^2\sqrt[3] {2xy^2}$

#### Work Step by Step

Simplify. $\sqrt[3]{16x^4y^8}$
Therefore, $\sqrt[3]{16x^4y^8}=\sqrt[3]{8x^3y^6} \cdot \sqrt[3] {2xy^2}$
or, $=\sqrt[3]{2^3x^3(y^2)^3} \sqrt[3] {2xy^2}$
Thus, the given radical term can be written as:$2xy^2\sqrt[3] {2xy^2}$