Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Test - Page 578: 19


$\dfrac{\sqrt[3] {25x}}{x}$

Work Step by Step

Simplify. $\dfrac{5}{ \sqrt [3]{5x^2}}$ Now, $\dfrac{5}{ \sqrt [3]{5x^2}}=(\dfrac{5}{ \sqrt [3]{5x^2}}) \cdot (\dfrac{\sqrt[3]{25x}}{ \sqrt[3]{25x}})$ or, $=\dfrac{5 \sqrt[3] {25x}}{5x}$ Thus, the given radical term can be written as: $\dfrac{\sqrt[3] {25x}}{x}$
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