Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Test - Page 578: 3



Work Step by Step

Simplify. $(25x^{\frac{-1}{2}}y^{\frac{1}{4}})^{\frac{1}{2}}$ $(25x^{\frac{-1}{2}}y^{\frac{1}{4}})^{\frac{1}{2}}=(25)^{\frac{1}{2}}(x^{\frac{-1}{2}})^{\frac{1}{2}}(y^{\frac{1}{4}})^{\frac{1}{2}}$ or, $=5(x)^{\frac{-1}{4}}y^{\frac{1}{8}}$ Thus, $=5(\dfrac{1}{\sqrt[4]x})(\sqrt[8]y)$ It can be written as $\dfrac{5\sqrt[8]y}{\sqrt[4]x}$
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