## Intermediate Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 7 - Test - Page 578: 3

#### Answer

$\dfrac{5\sqrt[8]y}{\sqrt[4]x}$

#### Work Step by Step

Simplify. $(25x^{\frac{-1}{2}}y^{\frac{1}{4}})^{\frac{1}{2}}$ $(25x^{\frac{-1}{2}}y^{\frac{1}{4}})^{\frac{1}{2}}=(25)^{\frac{1}{2}}(x^{\frac{-1}{2}})^{\frac{1}{2}}(y^{\frac{1}{4}})^{\frac{1}{2}}$ or, $=5(x)^{\frac{-1}{4}}y^{\frac{1}{8}}$ Thus, $=5(\dfrac{1}{\sqrt[4]x})(\sqrt[8]y)$ It can be written as $\dfrac{5\sqrt[8]y}{\sqrt[4]x}$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.