Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Test - Page 578: 27



Work Step by Step

Solve.$(3-4i) (2+5i)$ Need to drop the parentheses and multiply the terms. we have, $=3 (2+5i)-4i(2+5i)$ or, $=6+15i-8i-20i^2$ Since, $i^2=-1$ Hence, $=26+7i$
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