Answer
$4,1,-1$
Work Step by Step
Given: $x^3-4x^2-x+4=0$
or, $=x^2(x-4)-1(x-4)$
Take the common terms out.
or,$(x-4)(x^2-1)=0$
or,$(x-4)(x-1)(x+1)=0$
Set the each factor equal to zero, we have
Hence, $x=4,1,-1$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Test - Page 402: 37
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