## Intermediate Algebra for College Students (7th Edition)

$16y^2-56y+49$
Given: $(4y-7)^2$ Open the given polynomials by applying sum formula of polynomials such as: $(a+b)^2=a^2+b^2+2ab$ Thus, $(4y-7)^2=(4y)^2-2(4y)(7)+(7)^2$ Hence, $=16y^2-56y+49$