Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Test - Page 402: 12



Work Step by Step

Given: $(4y-7)^2$ Open the given polynomials by applying sum formula of polynomials such as: $(a+b)^2=a^2+b^2+2ab$ Thus, $(4y-7)^2=(4y)^2-2(4y)(7)+(7)^2$ Hence, $=16y^2-56y+49$
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