Answer
$-1,\dfrac{6}{5}$
Work Step by Step
Given: $(5x+4)(x-1)=2$
or,$5x^2-x-6=0$
or, $5x^2-6x+5x-6=0$
or,$(x+1)(5x-6)=0$
Set the each factor equal to zero, we have
$x=-1,\dfrac{6}{5}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Test - Page 402: 35
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