Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Test - Page 402: 18

Answer

$(x+3),(x-5),(x+5)$

Work Step by Step

Given: $x^3+3x^2-25x-75$ Take the common terms out. $=(x+3)(x^2-25)$ Since, $a^2-b^2=(a-b)(a+b)$ This implies, $(x+3)(x^2-25)=(x+3)(x^2-5^2)$ Hence, factors are:$(x+3),(x-5),(x+5)$
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