Answer
$x^2-9y^2+4x+4$
Work Step by Step
Given: $[(x+2)+3y][(x+2)-3y]$
Since, $a^2-b^2=(a-b)(a+b)$
Thus, $[(x+2)+3y][(x+2)-3y]=(x+2)^2-(3y)^2$
or,$=x^2+4+4x-9y^2$
Hence, $=x^2-9y^2+4x+4$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Test - Page 402: 13
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