#### Answer

$4x^2y,(3y^3+2xy-9)$

#### Work Step by Step

Given: $12x^2y^4+8x^3y^2-36x^2y$
Take $4xy$ as common
Thus, $=4x^2y(3y^3+2xy-9)$
Hence, factors are: $4x^2y,(3y^3+2xy-9)$

Published by
Pearson

ISBN 10:
0-13417-894-7

ISBN 13:
978-0-13417-894-3

$4x^2y,(3y^3+2xy-9)$

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