Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Test - Page 402: 29



Work Step by Step

Given: $12x^2y^4+8x^3y^2-36x^2y$ Take $4xy$ as common Thus, $=4x^2y(3y^3+2xy-9)$ Hence, factors are: $4x^2y,(3y^3+2xy-9)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.