Answer
$4x^2y,(3y^3+2xy-9)$
Work Step by Step
Given: $12x^2y^4+8x^3y^2-36x^2y$
Take $4xy$ as common
Thus, $=4x^2y(3y^3+2xy-9)$
Hence, factors are: $4x^2y,(3y^3+2xy-9)$
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