## Intermediate Algebra for College Students (7th Edition)

$4x^2y,(3y^3+2xy-9)$
Given: $12x^2y^4+8x^3y^2-36x^2y$ Take $4xy$ as common Thus, $=4x^2y(3y^3+2xy-9)$ Hence, factors are: $4x^2y,(3y^3+2xy-9)$