Answer
$(9y-5), (9y+5)$
Work Step by Step
Given: $81y^2-25$
Since, $a^2-b^2=(a-b)(a+b)$
This implies,
$81y^2-25=(9y)^2-(5)^2$
we have $=(9y-5)(9y+5)$
Hence, factors are:$(9y-5), (9y+5)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Test - Page 402: 17
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