Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Test - Page 402: 16


$x^2, (14x-15)$

Work Step by Step

Given: $14x^3-15x^2$ Take the common terms out. We have $=x^2(14x-15)$ Hence, factors are:$x^2, (14x-15)$
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