Answer
$y,(y^2+2),(y-3)$
Work Step by Step
Given: $y^4-3y^3+2y^2-6y$
Take the common terms out.
or, $=y(y^3-3y^2+2y-6)$
or,$=y[(y^2(y-3)+2(y-3)]$
or,$=y(y^2+2)(y-3)$
Hence, factors are: $y,(y^2+2),(y-3)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Test - Page 402: 33
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