Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Test - Page 402: 14



Work Step by Step

$f(x) \cdot g(x)=(x+2) \cdot (3x-5)$ This gives $=3x^2+x-10$ Plug $x=-5$ Then $f(-5) \cdot g(-5)=(-5+2) \cdot (3(-5)-5)=(-3)(-20)=60$
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