## Intermediate Algebra for College Students (7th Edition)

$(x-3y+5),(x+3y+5)$
Given: $x^2+10x+25-9y^2$ Take the common terms out. $=(x)^2+(2)(5)(x)+(5)^2-(3y)^2$ Open the given polynomials by applying sum formula of polynomials such as: $(a+b)^2=a^2+b^2+2ab$ This implies $=(x+5)^2-(3y)^2$ Since, $a^2-b^2=(a-b)(a+b)$ Thus,$=(x+5-3y)(x+5+3y)$ Hence, factors are:$(x-3y+5),(x+3y+5)$