Answer
$(x-3y+5),(x+3y+5)$
Work Step by Step
Given: $x^2+10x+25-9y^2$
Take the common terms out.
$=(x)^2+(2)(5)(x)+(5)^2-(3y)^2$
Open the given polynomials by applying sum formula of polynomials such as: $(a+b)^2=a^2+b^2+2ab$
This implies
$=(x+5)^2-(3y)^2$
Since, $a^2-b^2=(a-b)(a+b)$
Thus,$=(x+5-3y)(x+5+3y)$
Hence, factors are:$(x-3y+5),(x+3y+5)$
