Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Test - Page 402: 30

Answer

$(x^3+2)(x^3-14)$.

Work Step by Step

The given expression is $=x^6-12x^3-28$ Rewrite the middle term $-12x^3$ as $-14x^3+2x^3$. $=x^6-14x^3+2x^3-28$ Group the terms. $=(x^6-14x^3)+(2x^3-28)$ Factor from each term. $=x^3(x^3-14)+2(x^3-14)$ Factor out $(x^3-14)$. $=(x^3-14)(x^3+2)$ Rearrange. $=(x^3+2)(x^3-14)$.
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