Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.3 - The Algebra of Functions - Exercise Set: 62

Answer

$-4$

Work Step by Step

$f(2)=0, g(2)=1, f(0)=-2, g(0)=4$ $(fg)(2)=f(2)g(2)=0\times1=0$ $(\frac{g}{f})(0)=\frac{g(0)}{f(0)}=\frac{4}{-2}=-2$ $(fg)(2)-((\frac{g}{f})(0))^{2}=0-(-2)^{2}=0-4=-4$
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