Answer
$-4$
Work Step by Step
$f(2)=0, g(2)=1, f(0)=-2, g(0)=4$
$(fg)(2)=f(2)g(2)=0\times1=0$
$(\frac{g}{f})(0)=\frac{g(0)}{f(0)}=\frac{4}{-2}=-2$
$(fg)(2)-((\frac{g}{f})(0))^{2}=0-(-2)^{2}=0-4=-4$
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