## Intermediate Algebra for College Students (7th Edition)

$(-\infty,6)\cup(6,+\infty))$
$f(x)+g(x)=3x+7+\frac{2}{x-6}$ simplify $\frac{(3x+7)(x-6)+2}{(x-6)}=\frac{3x^2-11x-40}{x-6}$ since the denominator can't be equal to 0 $x\ne6$