Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.3 - The Algebra of Functions - Exercise Set - Page 133: 61

Answer

Hence, the answer is $-4$.

Work Step by Step

From the table values are $f(-2)=5,g(-2)=0,f(1)=−6,g(1)=-3$ $(fg)(-2)=f(-2)\times g(-2)=5×0=0$ $(\frac{f}{g})(1)=\frac{f(1)}{g(1)}=\frac{-6}{-3}=2$ $=(fg)(-2)−\left [ \left ( \frac{f}{g} \right )(1) \right ]^2$ Substitute all values. $=0−\left [ 2 \right ]^2$ $ = -4 $.
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