## Intermediate Algebra for College Students (7th Edition)

Hence, the answer is $-4$.
From the table values are $f(-2)=5,g(-2)=0,f(1)=−6,g(1)=-3$ $(fg)(-2)=f(-2)\times g(-2)=5×0=0$ $(\frac{f}{g})(1)=\frac{f(1)}{g(1)}=\frac{-6}{-3}=2$ $=(fg)(-2)−\left [ \left ( \frac{f}{g} \right )(1) \right ]^2$ Substitute all values. $=0−\left [ 2 \right ]^2$ $= -4$.