Answer
$(\frac{f}{g})(x)=\frac{x^{2}+4x}{2-x}$
$(\frac{f}{g})(3)=-21$
Work Step by Step
$(\frac{f}{g})(x)=\frac{f(x)}{g(x)}$
$=\frac{x^{2}+4x}{2-x}$
Plugin $x=3$ into $\frac{x^{2}+4x}{2-x}$.
$(\frac{f}{g})(3)=\frac{3^{2}+4\times3}{2-3}=\frac{9+12}{-1}=\frac{21}{-1}=-21$
