Answer
$(-\infty,6)\cup(6,+\infty)$
Work Step by Step
$f(x)+g(x)=3x+7+\frac{2}{x-6}$ simplify
$ \frac{(3x+7)(x-6)+2}{x-6}=\frac{3x^2-11x-40}{x-6}$ since the denominator can't be equal to 0 $x\ne6$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 2 - Section 2.3 - The Algebra of Functions - Exercise Set - Page 133: 22
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