Answer
$(-\infty,2)\cup(2,+\infty)$
Work Step by Step
$\frac{f(x)}{g(x)}=\frac{x^2+4x}{2-x}$ the denominator can't be equal to zero $x\ne2$
$(-\infty,2)\cup(2,+\infty)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 2 - Section 2.3 - The Algebra of Functions - Exercise Set - Page 133: 49
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