Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.3 - The Algebra of Functions - Exercise Set - Page 133: 41



Work Step by Step

$(fg)(x)=f(x)g(x)$ $(fg)(5)=f(5)g(5)$ First, find $f(5)$ and $g(5)$. $f(5)=5^{2}+4\times5=25+20=45$ $g(5)=2-5=-3$ Then, multiply them. $(fg)(5)=f(5)g(5)=45\times(-3)=-135$
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