Answer
$(\frac{f}{g})(x)=\frac{x^{2}+4x}{2-x}$
$(\frac{f}{g})(1)=5$
Work Step by Step
$(\frac{f}{g})(x)=\frac{f(x)}{g(x)}$
$=\frac{x^{2}+4x}{2-x}$
Plugin $x=1$ into $\frac{x^{2}+4x}{2-x}$.
$(\frac{f}{g})(1)=\frac{1^{2}+4\times1}{2-1}=\frac{1+4}{1}=\frac{5}{1}=5.$