Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.3 - The Algebra of Functions - Exercise Set: 43

Answer

$(\frac{f}{g})(x)=\frac{x^{2}+4x}{2-x}$ $(\frac{f}{g})(1)=5$

Work Step by Step

$(\frac{f}{g})(x)=\frac{f(x)}{g(x)}$ $=\frac{x^{2}+4x}{2-x}$ Plugin $x=1$ into $\frac{x^{2}+4x}{2-x}$. $(\frac{f}{g})(1)=\frac{1^{2}+4\times1}{2-1}=\frac{1+4}{1}=\frac{5}{1}=5.$
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