Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.3 - The Algebra of Functions - Exercise Set: 53

Answer

$(fg)(2)=-1$

Work Step by Step

When you see graph, you can see that $f(2)=-1$ and $g(2)=1$. $(fg)(2)=f(2)g(2)$ $=-1\times1$ $=-1$
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