Answer
$(-\infty,0)\cup(0,6)\cup(6,+\infty)$
Work Step by Step
$f(x)+g(x)=\frac{1}{x}+\frac{2}{x-6}$ simplify
$ \frac{x-6+2x}{x(x-6)}=\frac{3x-6}{x(x-6)}$ since the denominator can't be equal to 0 $x\ne0 x\ne6$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 2 - Section 2.3 - The Algebra of Functions - Exercise Set - Page 133: 24
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