## Intermediate Algebra for College Students (7th Edition)

$(fg)(-2)=-16$
$(fg)(x)=f(x)g(x)$ $(fg)(-2)=f(-2)g(-2)$. First, find $f(-2)$ and $g(-2)$. $f(-2)=(-2)^{2}+4\times(-2)=4-8=-4$ $g(-2)=2-(-2)=2+2=4$ Then, multiply them. $(fg)(-2)=f(-2)g(-2)=-4\times4=-16$