Answer
$(\frac{f}{g})(-1)=-1$
Work Step by Step
$(\frac{f}{g})(x)=\frac{f(x)}{g(x)}$
$=\frac{x^{2}+4x}{2-x}$
Plugin $x=-1$ into $\frac{x^{2}+4x}{2-x}.$
$(\frac{f}{g})(-1)=\frac{(-1)^{2}+4\times(-1)}{2-(-1)}=\frac{1-4}{2+1}=\frac{-3}{3}=-1$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 2 - Section 2.3 - The Algebra of Functions - Exercise Set - Page 133: 45
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