Answer
$(f+g)(x)=x^{2}+3x+2$
$(f+g)(3)=20$
Work Step by Step
$(f+g)(x)=f(x)+g(x)$
$=x^{2}+4x+2-x$
$=x^{2}+3x+2$
Plug in $x=3$ into $x^{2}+3x+2$.
$(f+g)(3)=3^{2}+3\times3+2=9+9+2=20$
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