Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.4 Solving Radical Equations - 8.4 Exercises - Page 654: 69

Answer

$x= 1 $

Work Step by Step

Given \begin{equation} \sqrt{7 x+2}=3. \end{equation} First square both sides to eliminate the radical sign and solve for $x$. \begin{equation} \begin{aligned} \sqrt{7 x+2}&=3\\ \left(\sqrt{7 x+2}\right)^2&= 3^2\\ 7 x+2& = 9 \\ x&= \frac{9-2}{7}\\ & = 1. \end{aligned} \end{equation} Check. \begin{equation} \begin{aligned} \sqrt{7 \cdot 1+2}&\stackrel{?}{=}3\\ 3& =3\quad \checkmark. \end{aligned} \end{equation} The solution is $x= 1 $.
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