Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.4 Solving Radical Equations - 8.4 Exercises - Page 654: 44

Answer

$x=36$

Work Step by Step

Add $\sqrt{x}$ on both sides. $\sqrt{x-11}=\sqrt{x}-1$ Square both sides. $x-11=(\sqrt{x}-1)^2$ $x-11=x-2\sqrt{x}+1$ $2\sqrt{x}=12$ $\sqrt{x}=6$ Square both sides $x=36$ Check: $\sqrt{36-11}-\sqrt{36}\stackrel{?}{=}-1$ $\sqrt{25}-6\stackrel{?}{=}-1$ $5-6\stackrel{?}{=}-1$ $-1=-1\checkmark$
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