Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.4 Solving Radical Equations - 8.4 Exercises - Page 654: 65

Answer

$x= 24.6 $

Work Step by Step

Given \begin{equation} \sqrt[3]{5 x+2}+7=12. \end{equation} Start by rewriting the radical as a power of fraction and then solve for $x$. \begin{equation} \begin{aligned} \sqrt[3]{5 x+2}+7&=12\\ \left(5 x+2\right)^{\frac{1}{3}}&= 5\\ \left(\left(5 x+2\right)^{\frac{1}{3}}\right)^3& = \left( 5\right)^3 \\ 5 x+2& =125\\ x&= \frac{125-2}{5}\\ & = 24.6. \end{aligned} \end{equation} Check. \begin{equation} \begin{aligned} \sqrt[3]{5 (24.6)+2}+7&\stackrel{?}{=}12\\ 12& =12\quad \checkmark. \end{aligned} \end{equation} The solution is $x= 24.6 $.
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