Answer
$= -\frac{4(n+6)}{(2n-3)}$
Work Step by Step
$\frac{2n+12}{4-3n} \div \frac{4n-6}{12n-16}$
$= \frac{2n+12}{4-3n} \times \frac{12n-16}{4n-6}$
$= \frac{2(n+6)}{4-3n} \times \frac{4(3n-4)}{2(2n-3)}$
$= \frac{2(n+6)}{4-3n} \times \frac{4(-(4-3n))}{2(2n-3)}$
$= \frac{2(n+6)}{1} \times \frac{-4}{2(2n-3)}$
$= -\frac{4(n+6)}{(2n-3)}$