Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 7 - Rational Functions - 7.3 Multiplying and Dividing Rational Expressions - 7.3 Exercises - Page 580: 20

Answer

$= \frac{(m-8)}{(m-3)}$

Work Step by Step

$\frac{m^{2}+6m+9}{m^{2}+5m+6} \times \frac{m^{2}-6m-16}{m^{2}-9}$ $= \frac{(m+3)(m+3)}{(m+3)(m+2)} \times \frac{(m-8)(m+2)}{(m+3)(m-3)}$ $= \frac{(m+3)(m+3)(m-8)(m+2)}{(m+3)(m+2)(m+3)(m-3)}$ $= \frac{(m+3)(m-8)(m+2)}{(m+2)(m+3)(m-3)}$ $= \frac{(m-8)(m+2)}{(m+2)(m-3)}$ $= \frac{(m-8)}{(m-3)}$
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