Answer
$= \frac{(c-11)}{(c+2)} $
Work Step by Step
$\frac{(c-3)(c+6)}{(c-7)(c+2)} \times \frac{(c-7)(c-11)}{(c+6)(c-3)}$
$= \frac{(c-3)(c+6)(c-7)(c-11)}{(c-7)(c+2)(c+6)(c-3)} $
$= \frac{(c+6)(c-7)(c-11)}{(c-7)(c+2)(c+6)} $
$= \frac{(c+6)(c-11)}{(c+2)(c+6)} $
$= \frac{(c-11)}{(c+2)} $