## Intermediate Algebra: Connecting Concepts through Application

$= -\frac{(3x+5)}{(x+2)}$ Frank thought that $(7-x) = (x-7)$, when in fact that is not true. Instead, Frank should have multiplied $(7-x)$ by $1=-1*(-1)$ to obtain $-1(x-7)$.
Frank thought that $(7-x) = (x-7)$, when in fact that is not true. Instead, Frank should have multiplied $(7-x)$ by $1=-1*(-1)$ to obtain $-1(x-7)$. $\frac{3x+5}{x-7} \times \frac{7-x}{x+2}$ $= \frac{(3x+5)(7-x)}{(x-7)(x+2)}$ $= \frac{(3x+5)(-(x-7))}{(x-7)(x+2)}$ $= \frac{-(3x+5)}{(x+2)}$ $= -\frac{(3x+5)}{(x+2)}$